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34kurt
3 years ago
10

Elyssa bought a rectangular aquarium . The measurements , in feet (ft) , are shown below. How much water will it take to fill th

e aquarium?
Mathematics
2 answers:
Andrews [41]3 years ago
6 0

Answer:

34 13/20

Step-by-step explanation:

Natasha_Volkova [10]3 years ago
3 0

Answer: The answer is 34 13/20.

Step-by-step explanation:

I did it and was correct for me! Hope it helps ❤️

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Solve for x.<br> x + 1 = 2<br> Ox= 1/4<br> O x= 1/2<br> O x = -1/2<br> 0 x = -1/4
Bogdan [553]

Answer:

x=-1/2

Step-by-step explanation:

7 0
3 years ago
Find the equation of the line that passes through points a and b :D
Nata [24]
The answer is y=2x-1



7 0
3 years ago
Read 2 more answers
URGENT LOL PLS HELP
Evgen [1.6K]

Answer:

{3x}^{2}  + 24x - 6

Step-by-step explanation:

To find the area of a rectangle you have to multiply the length by the width.

In your problem, the length and width are both equations, so you just have to multiply each part of the equation separately.

For example, if you were to put both equations with one over the other, you just have to multiply the aligned numbers.

The length is: x2 + 6x + 3

The width is: 3x2 + 4x - 2

and if you multiply the aligned numbers together, you get

3x2 + 24x - 6. Because:

x2 × 3x2 = 3x2,

6x × 4x = 24x,

and 3 × -2 = -6

6 0
3 years ago
Read 2 more answers
Show your work 2 1/5 × 3 1/8
vesna_86 [32]

Solution

For this case we can do the following:

2\cdot\frac{1}{5}=\frac{2\cdot5+1}{5}=\frac{11}{5}3\cdot\frac{1}{8}=\frac{3\cdot8+1}{8}=\frac{25}{8}

And then if we multiply we got:

\frac{11}{5}\cdot\frac{25}{8}=\frac{55}{8}

4 0
1 year ago
Find the absolute extreme of the function on the closed interval. y=9e^xsinx , [0,pi]
Molodets [167]

For convenience sake, I will let y=f(x)=9e^{x}\sin x

First, we evaluate the function at the endpoints of the interval.

f(0)=9e^{0}\sin(0)=0\\\\f(\pi)=9e^{\pi}\sin(\pi)=0

Then, we need to find the critical points.

We can start by taking the derivative using the power rule.

f'(x)=9e^{x} \frac{d}{dx} \sin x+9\sin x \frac{d}{dx} e^{x}=9e^{x}(\cos x+\sin x)

Setting this equal to 0,

9e^x (\cos x+\sin x)=0

Since 9e^x > 0, we can divide both sides by 9e^x.

\cos x+\sin x=0\\\\\sin x=-\cos x\\\\\tan x=-1\\\\x=\frac{3\pi}{4}

f\left(\frac{3\pi}{4} \right)=9e^{3\pi/4}\sin \left(\frac{3\pi}{4} \right)=\frac{9\sqrt{2}e^{3\pi/4}}{2}

So, the absolute minimum is \boxed{\left(\frac{3\pi}{4}, \frac{9\sqrt{2}e^{3\pi/4}}{\sqrt{2}} \right)} and the absolute minima are \boxed{(0,0), (\pi, 0)}

3 0
1 year ago
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