Answer:
Part A) The area total of the design is 
Part B) The total area of the four large shaded triangles is 
Part C) The cost to purchase the material to make the triangles for the quilt will be 
Step-by-step explanation:
Part A) Find the area total of the design
The area total of the design is a square
so
To find the length side of the square design multiply the number of squares by 3 in
Part B) Find the total area of the four large shaded triangles
the area of the four large triangles is equal to
![A=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=A%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have that
substitute
![A=4[\frac{1}{2}(6)(6)]=72\ in^{2}](https://tex.z-dn.net/?f=A%3D4%5B%5Cfrac%7B1%7D%7B2%7D%286%29%286%29%5D%3D72%5C%20in%5E%7B2%7D)
Part C) How much will it cost to purchase the material to make the triangles for the quilt ?
To find the cost multiply the area of each design of four large triangles by 30 and then multiply by $0.08 per square inch
The cost is equal to
<span>If the interest is comounded every 2 months then you will
apply the interest 6 times in a year. So the value of n that you will plug into
your equation is 6 because there 12 months a year then it wll be compounded
every 2 months</span>
1 worker = 30 hours a week
1 worker = 30 x $5.50 a week = $165
1 worker = $165
1000 workers = 165 x 1000 = $165 000
2. -11 sq rt of 112
Sq rt of 16 times sq rt of 7
Becomes 4 sq rt of 7
Multiply -11 times 4 sq rt of 7
-44 sq rt of 7
Answer A
3. Subtract 17-9 since they are hitch the same sq rt
Answer 8 sq rt of 17
Answer:
![\left[\begin{array}{ccc}3&-5 &|12\\4&-2 &|15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%20%20%26%7C12%5C%5C4%26-2%20%20%26%7C15%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
When making a matrix of two equations with the variables x and y, the result will be a matrix with three columns:
- a column for the values of x in each equation
- a column for the values of y in each equation
- a column for the independent values of each equation
since our system of equations is:
we can see that the value for x in the first equation is 3 and in the second equation is 4, thus the first column will have the numbers 3 and 4:
![\left[\begin{array}{ccc}3&&\\4&&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26%26%5C%5C4%26%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now for the values of y we hvae -5 in the first equation and -2 in the second equation, we update the matrix with another column with the values of -5 and -2:
![\left[\begin{array}{ccc}3&-5&\\4&-2&\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%26%5C%5C4%26-2%26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Finally, the last column is the independent values of each equation (or the results) in the first equation that number is 12 and in the second equation is 15, thus the matrix is:
![\left[\begin{array}{ccc}3&-5&12\\4&-2&15\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%2612%5C%5C4%26-2%2615%5C%5C%5Cend%7Barray%7D%5Cright%5D)
usually there is a line separating the columns for the values of x and y, and the independent values:
this is the matrix of the system of equations
