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Nady [450]
4 years ago
6

What is the probability that a fair die never comes up an even number when it is rolled six times? (note: enter the value of pro

bability in decimal format and round it to three decimal places.)?
Mathematics
1 answer:
seropon [69]4 years ago
6 0
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:

Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.

Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64

Therefore, the probability is 1/64 or 1.56%.
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Find the area.<br> 5 cm<br> 5 cm<br> 16 cm---<br> 7 cm<br> 14 cm
zalisa [80]

Answer:

if it is area of triangle it would be 49

Step-by-step explanation:

3 0
3 years ago
What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid
devlian [24]
<h3>Answer:</h3><h3>Exact area = \frac{3}{2}\sqrt{3} square cm</h3><h3>Approximate area = 2.598 square cm</h3>

=================================================

Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

A = \frac{\sqrt{3}}{4}*s^2

A = \frac{\sqrt{3}}{4}*1^2

A = \frac{\sqrt{3}}{4}

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

6*A = 6*\frac{\sqrt{3}}{4}

6A = \frac{3\sqrt{3}}{2}

6A \approx 2.598

4 0
3 years ago
What is the sum? –18+(–14)<br> a. –32<br> b. –4<br> c. 4<br> d. 32
Jlenok [28]
A.-32
Ignore the negatives and add. Then put back the negatives
6 0
4 years ago
Read 2 more answers
The formula can be used to find the velocity v in feet per second of an object that has fallen h feet. Find the velocity of an o
Mama L [17]
The formula for a falling object is
v = u +gt
where
u =  initial velocity (=0 for a falling object)
g =  acceleration due to gravity, 32.2 ft/s²
t = time, s

In terms of distance fallen,
v² = u² + 2gh
where h =  distance fallen, ft.

Because h = 23 ft and u = 0, therefore
v² = 2*32.2*23 =  1481.2
 v = 38.486 ft/s

Answer: 28.49 ft/s (nearest hundredth)
8 0
3 years ago
What is the equation of the line that passes<br> through the points (3,-1) and (7, 3)?
exis [7]

Answer: y = 1x + -4

Equation of a straight line:

y = mx + b ------(i)

Step by Step Solution:

Step 1: Calculating Slope (m).

m = y2-y1 /x2-x1

m = 3--1 /7-3

m = 4/4

m = 1

Now putting value of m in equation (i)

y = 1x + b -----(ii)

Step 2: Calculating Y-intercept (b).

Lets choose the first point, (3,-1) for calculating y-intercept:

y = mx + b

-1 = 1(3) + b

-1 = 3 + b

-4 = b

b = -4

Now putting value of b in equation (ii)

y = 1x + -4

4 0
2 years ago
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