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Nady [450]
3 years ago
6

What is the probability that a fair die never comes up an even number when it is rolled six times? (note: enter the value of pro

bability in decimal format and round it to three decimal places.)?
Mathematics
1 answer:
seropon [69]3 years ago
6 0
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:

Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.

Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64

Therefore, the probability is 1/64 or 1.56%.
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Hello I would really appreciate if someone could help me with this math question. I’m so confused
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Answer:

  a. f = 17.5/c

  b. 8.75 N

Step-by-step explanation:

<h3>(a)</h3>

Inverse variation means one variable is proportional to the inverse of the other. The equation for that is ...

  f = k(1/c) . . . . . . force (f) is proportional to the inverse of distance (c)

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  17.5 N·cm = k . . . . . . multiply by the denominator

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<h3>(b)</h3>

Using the above equation, we find the force to be ...

  f = 17.5/2 = 8.75 . . . . newtons

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<em>Additional comment</em>

We often look at several different kinds of proportionality:

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and there are combinations of these, such as ...

  • y = kr²h . . . . jointly proportional to h and the square of r

You may have noticed that when x and y are inversely proportional, their product is a constant. y = k/x  ⇒  xy = k

__

We have left off the units of k in the problem above. Sometimes it is a good idea to retain them, or to pay close attention to what they are. This can avoid using the wrong measures for the variables.

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tankabanditka [31]

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5 0
3 years ago
Read 2 more answers
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