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Ivan
3 years ago
10

What is the solution to the system of equations? 6x-2y=10 and y=3x-5

Mathematics
1 answer:
notsponge [240]3 years ago
7 0

Answer:

(2,1)

Step-by-step explanation:

X=2 and y=1

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6 = s

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What is not a multiple of 7
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⎧
d1i1m1o1n [39]

<u>Given</u>:

The given expression to find the nth term of the sequence is d(n)=d(n-1) \cdot (-5)

The first term of the sequence is d(1)=8

We need to determine the third term of the sequence.

<u>Second term:</u>

The second term of the sequence can be determined by substituting n = 2 in the nth term of the sequence.

Thus, we have;

d(2)=d(2-1) \cdot (-5)

d(2)=d(1) \cdot (-5)

d(2)=8 \cdot (-5)

d(2)=-40

Thus, the second term of the sequence is -40.

<u>Third term:</u>

The third term of the sequence can be determined by substituting n = 3 in the nth term of the sequence.

Thus, we have;

d(3)=d(3-1) \cdot (-5)

d(3)=-40 \cdot (-5)

d(3)=120

Thus, the third term of the sequence is 120.

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I need to know the answers for a, b, and c for 23.
Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

m∠1 = 50°

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Step-by-step explanation:

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Find the difference between8/15 and 2/3 Show all calculations in your final answer.
kherson [118]

Answer:

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}          

Step-by-step explanation:

  • Let the value of a number 'a' be = 8/15
  • Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

         =\frac{8}{15}-\frac{-2}{3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

          =\frac{8}{15}-\left(-\frac{2}{3}\right)

\mathrm{Apply\:rule}\:-\left(-a\right)=a

          =\frac{8}{15}+\frac{2}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

          =\frac{8+10}{15}

          =\frac{18}{15}

\mathrm{Cancel\:the\:common\:factor:}\:3

           =\frac{6}{5}

Thus,

  • \frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}                    
3 0
3 years ago
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