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3 years ago

The normal cost of a coat is £94 In a sale the cost of the coat is reduced by 36%

Mathematics

2 answers:

Hunter-Best [27]3 years ago

8 0

Answer:

£60.16

Step-by-step explanation:

94 decrease 36% =

94 × (1 - 36%) = 94 × (1 - 0.36) = 60.16

KATRIN_1 [288]3 years ago

3 0

Answer:

33.84

Step-by-step explanation:

Multiply 94 by .36

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Step-by-step explanation:

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3 years ago

What fraction of 2 1/2 is 48 minutes <br>

SIZIF [17.4K]

Answer:

19.2

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Use spherical coordinates. evaluate (9 − x2 − y2) dv, where h is the solid hemisphere x2 + y2 + z2 ≤ 4, z ≥ 0.

avanturin [10]

In spherical coordinates, we have

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}$

which gives volume element

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

and so the triple integral is given by

$\displaystyle\iiint_H(9-x^2-y^2)\,\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9-\rho^2\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$
$=\displaystyle2\pi\int_{\varphi=0}^{\varphi=\pi/2}\int_{\rho=0}^{\rho=2}(9\rho^2\sin\varphi-\rho^4\sin^3\varphi)\,\mathrm d\rho\,\mathrm d\varphi$
$=\dfrac{592\pi}{15}$

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3 years ago