Answer:
36.869 or 36.87
Step-by-step explanation:
first, you find which trig function you are using. in this case, tangent.
then, you put calculate the arctan(3/4) which is 36.96989765
Answer:
B and C
Step-by-step explanation:
25% of 64 is 16. So find the two answers that are equivalent to 16.
A: 25*64 = 1600
16
B:
*64 = 16
C: 0.25 * 64 = 16
D: 64/
=256
16
E: 25/
= 39.06
16
Part 1: the function would be
h(t)= -16t^2+15t+6.5
Part 2: using the same steps it stated on the calculator
x=1.26
Part 3: by using t= -b/(2a) 15 as b and -16 as a makes it
t= 15/32
Part 4: You then put 15/32 in for t in the equation making the maximum height
10.02
IDK IF THIS IS RIGHT BUT IVE SPENT ALL DAY ON THIS
The required equation of the surface area of the cylinder is 
<u>Solution:</u>
Let "r" be the radius of cylinder and "h" be the height.
Formula for surface area is:

where
is surface of two bases of cylinder and
is surface of mantle.
From the given, the height of the gift box is three times the radius, i.e 
On substituting the given values in the formula we get,
![S = 2\times\pi[(3x+4)^2 + (9x+12)\times(3x+4)]](https://tex.z-dn.net/?f=S%20%3D%202%5Ctimes%5Cpi%5B%283x%2B4%29%5E2%20%2B%20%289x%2B12%29%5Ctimes%283x%2B4%29%5D)
![\Rightarrow S=2\pi[(3x^2)+2\times3x\times4+4^2]+[(9x\times3x)+12\times3x+36x+48]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D2%5Cpi%5B%283x%5E2%29%2B2%5Ctimes3x%5Ctimes4%2B4%5E2%5D%2B%5B%289x%5Ctimes3x%29%2B12%5Ctimes3x%2B36x%2B48%5D)
![\Rightarrow S=2\pi[9x^2+24x+16]+[21x^2+36x+36x+48]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D2%5Cpi%5B9x%5E2%2B24x%2B16%5D%2B%5B21x%5E2%2B36x%2B36x%2B48%5D)
![\Rightarrow S=2\pi[9x^2+24x+16+21x^2+72x+48]\rightarrow2\pi[30x^2+96x+64]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D2%5Cpi%5B9x%5E2%2B24x%2B16%2B21x%5E2%2B72x%2B48%5D%5Crightarrow2%5Cpi%5B30x%5E2%2B96x%2B64%5D)
On multiplying
inside the brackets we get,
![\Rightarrow S=[60\pi x^2+192\pi x+128\pi]](https://tex.z-dn.net/?f=%5CRightarrow%20S%3D%5B60%5Cpi%20x%5E2%2B192%5Cpi%20x%2B128%5Cpi%5D)
Hence, the required equation is 