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3 years ago

Write 8 and 1/3 % as a fraction in simplified form.

Mathematics

1 answer:

Burka [1]3 years ago

3 0

Answer:

as a fraction i believe it would be 25/3, but correct me if im wrong :)

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Determine if the angles are greater than (>), less than (<), or equal (=) to each other.

Gwar [14]

Opposite side to <WYX=WX
Opposite side to <XWY=XY

Here

WX=12
XY=15

WX<XY

$\\ \sf\longmapsto$

4 0

3 years ago

Plz solve it And show ur work plzzz giving brainliest

miss Akunina [59]

Answer:

Step-by-step explanation:

4 x 6 1/4

4 x 25/4

= 25

5 0

3 years ago

Read 2 more answers

The sum of the squares of two consecutive integers is 145. Find the two integers.

worty [1.4K]

Answer: The two integers are 8 and 9.

Step-by-step explanation: Let n represent the number.

n^2 + (n + 1)^2 = 145

By foiling, this can be rearranged to:

n^2 + n^2 + 2n + 1 = 145

Subtract 145 from both sides:

2n^2 + 2n - 144 = 0

Divide both sides by 2:

n^2 + n - 72 = 0

Factor the polynomial:

(n + 9)(n - 8) = 0

Solve for n:

n = -9, n = 8

Since they need to be consecutive, make the 9 positive. It will be positive either way because it is being squared.

Now, n = 9 and n = 8.

These are your two integers. Hope this helps!

6 0

3 years ago

true or false, and explain: (a) If a die is rolled three times, the chance of getting at least one ace is 1/6 + 1/6 + 1/6 = 1/2.

guajiro [1.7K]

Answer:

a.False

b.False

Step-by-step explanation:

a.Total possible outcomes of a die=1,2,3,4,5,6=6

Probability of getting an ace= $\frac{favorable\;cases}{total\;number\;of\;cases}$

Favorable cases=1

Probability of getting an ace= $\frac{1}{6}$

A die is rolled three times .

We are given that the probability of getting at least one ace is

$\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{1}{2}$

There are using addition rule but it is not correct because addition rule used when the events are mutually exclusive .

The events are mutually exclusive when the events cannot occur at the same time.

Since it is possible to obtain one ace on more than one roll of a die.

Therefore, the events are not mutually exclusive.

Hence, the given statement is false.

b.Total cases in one coin=2(H,T)

Number of cases in favor of head=1

The probability of getting on head= $\frac{1}{2}$

The coin is tossed twice.

We are given that

If a coin is tossed twice ,the chance of getting at least on head is 100%.

There are using addition rule but it is not correct because addition rule used when the events are mutually exclusive .

The events are mutually exclusive when the events cannot occur at the same time.

Since it is possible to obtain head on both tosses of coin.

Therefore, the events are not mutually exclusive.

Hence, the given statement is false.

5 0

3 years ago

F(x) = (two-fifths) Superscript x g(x) = (two-fifths) Superscript x – 3 Which statement about f(x) and its translation, g(x), is

insens350 [35]

C .) The - 3 at the end of the function means the function is shifted down 3 units. This also shifts the asymptote down 3 units.

8 0

3 years ago

Read 2 more answers