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3 years ago

Need help asap will mark brainliest!

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

Answer:

the answer is E

Step-by-step explanation:

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BEST ANSWER GETS BRAINLIEST!! HELP PLEASE.

Goshia [24]

Answer:

$\text{The area of parallelogram is }8 ft^2$

$\text{The area of two triangles of equal area is }4 ft^2$

Step-by-step explanation:

Given a parallelogram ABCD is shown with DC equal to 9 feet and the perpendicular distance between AB and DC equal to 8 over 9 foot.

Part A: we have to find the area of ABCD.

$\text{Area of parallelogram=}Base\times height$

$=9\times \frac{8}{9}=8 ft^2$

$\text{The area of parallelogram is }8 ft^2$

Part B:

We have to decompose this parallelogram into two triangles.

Join diagonal AC

As the diagonal of parallelogram divides it into two congruent triangles of equal area

Hence, the area of each triangle is

$\frac{1}{2}ar(ABCD)$

$\frac{1}{2}\times 4=4 ft^2$

$\text{The area of two triangles of equal area is }4 ft^2$

3 0

3 years ago

Translate the problem into a mathematical sentence, using f as your variable name. Do not use spaces in your answer. (If necessa

IrinaVladis [17]

If you multiply those 8 (people) by 3 (the time each person gets in the interview)
you get 24 mins.

written as a mathematical sentence that would be: f=8*3

-hope it helps

8 0

4 years ago

Mary had five and one half dollars she spent two and one fourth dollars on a snack how much money does Mary have left

Daniel [21]

Answer:

3 and 1/4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A certain population is growing according to the formula N = 1330 × 1.09t. What is the tripling time for this population? Round

babunello [35]

Answer:

jeBeth indkkr kspdksnkensmskms

4 0

4 years ago

X² - 8x - 33=0<br> complete the square

Andreas93 [3]

<h2>Answer:</h2><h2></h2><h2> $\boxed{x_{1}=-3} \\ \\ \boxed{x_{2}=11}$ </h2>

<h2>Explanation:</h2>

Step 1. Write $x^2 - 8x - 33=0$ in the form $x^2+2ax+a^2=0$

$2a=-8\quad :\quad a=-4$

Step 2. Add and subtract $(-4)^2$ to the left side of the equation

$x^2-8x-33+\left(-4\right)^2-\left(-4\right)^2=0 \\ \\ \\ But: \\ \\ x^2+2ax+a^2=\left(x+a\right)^2 \\ \\ x^2-8x+\left(-4\right)^2=\left(x-4\right)^2$

Step 3. Complete square

$\left(x-4\right)^2-33-\left(-4\right)^2=0 \\ \\ \left(x-4\right)^2-49=0 \\ \\ (x-4)=\pm \sqrt{49} \\ \\ x-4=\pm 7 \\ \\ \boxed{x_{1}=-3} \\ \\ \boxed{x_{2}=11}$

8 0

3 years ago