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Harlamova29_29 [7]

3 years ago

14

Ms. Li Spent $840 on a vacation. she spent 2/3 of the amount on a train ticket and a 1/2 of the remaining amount on food.how muc

h did she spend on the ticket and food all together

1 answer:

nikitadnepr [17]3 years ago

5 0

She spent $700 on the train ticket and food. She has $140 left

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Help me please! Literally don’t understand the question.

andrey2020 [161]

I think it's d hope it helps

6 0

3 years ago

Read 2 more answers

A trapezoid has an area of 266.4 square feet. One base is 8.5 feet long. The height measures 24 feet. What is the length of the

exis [7]

266.4 - 8.5 - 24 will give you the answer of 233.9

6 0

3 years ago

PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Brums [2.3K]

The given matrix equation is,

$1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]$ .

Multiplying the matrices with the scalars, the given equation becomes,

$\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Adding the matrices,

$\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\$

Matrix equality gives,

$1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2$

Solving the equations together,

$y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10$

We can see that the equations are not consistent.

There is no solution.

3 0

3 years ago

Center(-3,-4) radius=10 plz help

vovikov84 [41]

Y+4=10(x+3)
Y+4=10x+30
Y=10x+26

7 0

3 years ago

The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice

777dan777 [17]

If period of $f(\theta)$ is one-half the period of $g(\theta)$ and
<span> $g(\theta)$ has a period of 2π, then $T_{g} =2T_{f}=2 \pi$ and $T_{f}= \pi$ .
</span>
To find the period of sine function $f(\theta)=asin(b\theta+c)$ we use the rule $T_{f}= \frac{2\pi}{b}$ .
<span /><span />
f is sine function where f (0)=0, then c=0; with period $\pi$ , then $f(\theta)=asin 2\theta$ , because $T_{f}= \frac{2 \pi }{2} = \pi$ .

To find a we consider the condition $f( \frac{ \pi }{4} )=4$ , from where $asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4$ .

If the amplitude of $f(\theta)$ is twice the amplitude of $g(\theta)$ , then $g(\theta)$ has a product factor twice smaller than $f(\theta)$ and while period of $g(\theta)$ <span> </span> is 2π and g(0)=0, we can write $g(\theta)=2sin\theta$ .

8 0

3 years ago