Two triangles have the same base lengths. One Triangle has the height that is 4 times the height of the other triangle. Are the
heights and the areas of the two triangles proportional?
1 answer:
YES
Base=b
Height= h
Area 1=A1=1/2*b*h
Base=b
Height= 4h
Area of triangle 2=A2=1/2*b*4h
A2/A1= (1/2*b*4h)/(1/2*b*h)
= (1/2*b*4h)/(1/2*b*h)
=4/1
Ratio of heights =h2/h1= 4/1
Ratio of areas =A2/A1= 4/1
They are proportional.
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