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Hitman42 [59]
3 years ago
12

The digits of a two-digit number sum to 8. When the digits are reversed, the resulting number is 18 less than the original numbe

r. What is the original number?
Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

53

Step-by-step explanation:

 Let x = the first digit

and y = the second digit. Then,

    xy = the number

We have two conditions:

(1) x + y = 8

(2) 10y + x = 10x + y - 18

Simplify (2)                     10y + x - 10x - y = -18

                                              (3) 9y - 9x  = -18

Multiply Equation (1) by 9     (4) 9x + 9y =  72

Add Equations (3) and (4)                18y =  54

Divide each side by 18         (5)           y =    3

Substitute (5) into (1)                       x + 3 =   8

Subtract 3 from each side                   x =   5

x = 5 and y = 3

The number is 53.

Check:

(1) 5 + 3 = 8     (2) 10×3 + 5 = 10×5 + 3 - 18

         8 = 8             30  + 5 =   50  + 3 - 18

                                      35 =       53    - 18

                                      35 =            35

xxMikexx [17]3 years ago
5 0

Answer:

53 add the 2 and you get 8

Step-by-step explanation:flip them 35 + 18 =53

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