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Nataliya [291]
3 years ago
8

Can someone help me with these

Mathematics
1 answer:
Stolb23 [73]3 years ago
6 0

Answer:

Problem 2) : the gradient is "-2", and the y-intercept is "3"

Problem 3)

A is  y=2x+2

B is y=x+2  

Step-by-step explanation:

Problem 2)

In the line given by the equation:   y=-2x+3

the "gradient" (also known as "slope") is the numerical coefficient that multiplies the variable "x". So in this case the gradient is "-2"

the y-intercept is the numerical term "+3" because that is the y-value result of evaluating the expression for x = 0

y=-2x+3\\y=-2\,(0)+3\\y=3

Problem 3)

Consider the two lines :

y=x+2  and  y=2x+2

notice that both have the same y-intercept (that is the numerical term "2" at the end of both expressions. That means that both lines cross the y-axis at the point y=2.

Now notice that the gradient of one of them is "1"  (for y=x+2 ) that is the coefficient that multiplies the variable "x". While for the other line ( y=2x+2)  the gradient is "2" and therefore steeper than the previous one.

Then, the line identified as "A" which is the one with steeper gradient, corresponds to the equation   y=2x+2, and the line identified with "B" is the one with smaller gradient  y=x+2  .

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For the linear function f(x) = -2x+1 , find the following
Leya [2.2K]

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The function is:

f(x)=-2x+1

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c. Graph the function, label x, and y-intercepts.

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Plot the points (0,1), \left(0.5,0\right) and connect them by a straight line as shown below:

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