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Vinil7 [7]
3 years ago
6

Can someone tell me what type of angle this is?

Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

Option a : supplementary angles

Step-by-step explanation:

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If (6^0)^x= 1 what are the possible outcomes of x? Explain your answer.
swat32
X can be any  real number 

As long as it is to the power of 0, it will equal one. And because 6^0 = 1, 1^x can be any positive number, and it will still give you one.

As stated by WojtekR, even negative numbers can get 1

x = - 5

(6^0)^-5 =  1^-5 = 1/1 = 1


~ Thanks @WojtekR
7 0
3 years ago
Factoring trinomials
Tcecarenko [31]

c^22c^2 + 13c +21 \\4c^2 + 13(2)c + 42\\(2c + 6)(2c+7)\\(c+3)(2c+7)


This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying  c^2. This is the second line. Then, you could take the square of the 4c^2, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)

In ? we put the corresponding numbers that, if we multiply them we will obtain 42, and if we add them we will obtain 13. This numbers are 6 and 7. Then, we have (2c + 6) (2c +7)

The last step is divide by the number that we multipy in the first step.

4 0
3 years ago
What is the volume of this cube?
Novay_Z [31]

Step-by-step explanation:

Use formula for cube volume:

V=a³

Then add informations you already have and you are done.

V=0,5³

V=0,125 m³

8 0
3 years ago
Read 2 more answers
Candice recorded outdoor temperature of -5°C -1°c,and -2°C which following correctly compares the three temperature
lisov135 [29]

-5°C < -2°C < -1°C

Look at the picture.

6 0
3 years ago
A, B &amp; C form a triangle where ∠ BAC = 90°. AB = 13.5 mm and CA = 3.2 mm. Find the length of BC, giving your answer rounded
adelina 88 [10]

Answer:

13.9

Step-by-step explanation:

Use Pythagorean Theorem:

Both of the lengths given are the legs,

13.5^2 + 3.2^2 = c^2

182.25 + 10.24 = c^2

192.49 = c^2

13.87 = c

8 0
3 years ago
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