Answer: uh.. 3?
Step-by-step explanation:
lol
Answer:
The z-score for an income of $2,100 is 1.
Step-by-step explanation:
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
Given:
µ = $2,000
σ = $100
<em>x</em> = $2,100
Compute the <em>z</em>-score for the raw score <em>x</em> = 2100 as follows:
Thus, the z-score for an income of $2,100 is 1.
Undo the X first...........
Answer:
A) 2x*2 +6x -3x - 9= 2x*2 +3x -9
B) 2yx*2 +2yx +2y +3x*2 +3x +3
C) 36x*2 y +48yx +3xy*2 + 4y*2
D) 2x*3 - 4x*2 y + 3x -6y
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
