the equation that we can solve using the given system of equations is:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
<h3>Which equation can be solved using the given system of equations?</h3>
Here we have the system of equations:
y = 3x^5 - 5x^3 + 2x^2 - 10x + 4
y = 4x^4 + 6x^3 - 11
Notice that both x and y should represent the same thing in both equations, then we could write:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = y = 4x^4 + 6x^3 - 11
If we remove the middle part, we get:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = 4x^4 + 6x^3 - 11
Now, this is an equation that only depends on x.
We can simplify it to get:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
That is the equation that we can solve using the given system of equations.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer/Step-by-step explanation:
To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.
Given, {2, 3, 5, 6, 10, 14, 15},
Minimum value = 2
Median = middle data point = 6
Q1 = 3 (the middle value of the lower part of the data set before the median)
Q3 = 14 (middle value of the upper part of the data set after the median)
Maximum value = 15
If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.
See the attachment below for the correct box plot.
Your answer will be letter c
a) because the denominators are the same add the numerators:
1 1/5 + 3 2/5 = 4 3/5
b) rewrite the fractions to have a common denominator:
1/2 = 3/6
1/3 = 2/6
Now subtract:
4 3/6 - 1 2/6 = 3 1/6
3x+6 I believe because you can’t add a number with a variable to a number without one
