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grandymaker [24]
3 years ago
11

NEED HELP!!

Mathematics
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

Options B, D, G are the answers.

Step-by-step explanation:

In the figure attached ΔABC and ΔADE are similar.

Now we will check each option given

A). AC = AB

AB = √(2² + 1²) = √5 [ By Pythagoras theorem ]

AC = √(2² + 2²) = √(4 + 4) = √8

Therefore option is not true.

B) \frac{AC}{AE}=\frac{BC}{DE}

In these triangles tanC=\frac{2}{2}=1

∠ C = 45°

and tanE = \frac{4}{4}=1

∠ E = 45°

Similarly ∠B = ∠D

Therefore, by theorem of similar triangles corresponding sides will be in the same ratio.

\frac{AC}{AE}=\frac{BC}{DE}

Option B is true.

C). \frac{AC}{AD}=\frac{AB}{AE}

Since we have proved the ratio of corresponding sides in option B. So this option is not true.

D). DE = 2BC

DE = 4 - (-2) = 4 + 2 = 6 units

BC = 2 - (-1) = 2 + 1 = 3 units

So DE = 6 = 2×3 = 2BC

Therefore, this option is true.

E). BC = 2DE

This option is not correct because DE = 2BE

F). AC = 2AE

AC = √8 = 2√2

AE = √(4² + 4²) = √(16+16)

     = √32 = 4√2

Here AC is smaller so this option is not true.

G). AE = 2AC

Since AC = 2√2

and AE = 4√2

Therefore, AE = 2AC

So this option is true.

Finally Options B, D, G are correct.

Marrrta [24]3 years ago
3 0

AC/AE = BC/DE

DE = 2BC

AE = 2AC


Those are your answers. I( hope this helped!

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Answer:

a)

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

b)

The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where

P represents the principal amount

r represents Annual Rate

n represents the number of compounding periods per unit t, at the end of each period

t represents the time Involve

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Given

The principal amount  P = $4200

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Compounded monthly = n = 12

Time Period = t

To Determine:

The total amount A = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

substituting the values

A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}

\:A\:=\:4200\left(1.0025\right)^{120}

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Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

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