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3 years ago

EASY 8TH GRADE MATH. 16 POINTS

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

5 0

Answer: lol, I tried solving this but this is harder then what I had in 8th grade.

Step-by-step explanation:

Vesnalui [34]3 years ago

3 0

Answer:

steve is 23 and julie is 28

Step-by-step explanation:

51 - 5 = 46

46/2 = 23

steve is 23, but julie is 5 years older than him, so

23 + 5 = 28

28+23=51

hope this helps!!!

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Which representation would be best for determining between which two values 50% of the data will lie?

trapecia [35]

Step-by-step explanation:

My Own Answer please make me Brianliest

8 0

2 years ago

Factor the trinomial below.

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

yes, we need two numbers that multiplied with each other results in -48.

that means already that one of them has to be positive and the other negative.

that gives us (with all +/- alternating sign combinations)

2 and 24

3 and 16

4 and 12

6 and 8

to pick from there we see that the "middle" term is -2x.

that means that the absolute value of the negative number has to be 2 more than the positive number (so that when adding the intermediate multiplication terms we end up with -2x).

the only choice is therefore 6 and -8.

and that makes B the right answer.

3 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

4 0

3 years ago

The mass of a particular substance is known to grow exponentially at a rate of 1.5% per day. Its initial mass was 230 grams and,

Papessa [141]

Answer:

23 days

Step-by-step explanation:

Given that the mass of a particular substance is known to grow exponentially at a rate of 1.5% per day

Initial mass = $230 gm$

After t days, mass = $325 gm$

The equation is

$P(t) = 325 = 230 (1+\frac{1.5}{100} )^t\\\frac{325}{230} =1.015^t\\log 1.413 = t log 1.015\\t = \frac{log 1.413}{log 1.015} =\frac{0.1502}{0.0065} \\=23.229$