If 945 is the product of 5 CONSECUTIVE ODD numbers, let's find the prime factors of 945:
945 = 5 x 7 x 27 , but we need 5 odd numbers:
945= 5 x 7 x ( 3 x 9 ) we still need one factor. This factor cannot be but 1
945 = 1 x 3 x 5 x 7 x 9 = 945 and the greatest value of these integers is 9
Answer:

Step-by-step explanation:
we are given

we can simplify left side and make it equal to right side
we can use trig identity


now, we can plug values

now, we can simplify



now, we can factor it

![\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%28sin%5E2%28a%29%2Bcos%5E2%28a%29-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can use trig identity

![\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%281-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can cancel terms

now, we can simplify it further




now, we can use trig identity

we can replace it

so,

1 = Hundred tens of thousandths.
0 = tens of thousandths.
6 = thousandths.
5 = hundredths.
3 = tenths.
4 = units.
Answer:
0.3
Step-by-step explanation: