What is the angle of rotation of the figure? A.0° B.90° C.120° D.180°

Suppose a researcher is testing to see if a basketball player can make free throws at a rate higher than the NBA average of 75%.

stich3 [128]

Answer: A. Repeated results if the player makes 75% of his shots in the long run.

Step-by-step explanation:

The null distribution is always the opposite of the alternative distribution which in most cases represents the claim or hypothesis which is to be tested or performed. In the scenario given, the challenge is to show that a basketball player has an average higher than that of the NBA. NBA average stands at 75%. The alternative hypothesis is the claim, which is ;

H1 : μ > 75%

THE null is thus :

H0 : μ = 75% ; which means that repeated result of the player will yields an average of 75%

3 0

3 years ago

Caiden wants to use the distributive property to find the value of 28⋅19+28⋅6528·19+28·65. Which expression can he use?

MakcuM [25]

28 times 28 times (19+65)

4 0

4 years ago

M find b a) not triangle b)11in c)14in d)13in

Alexxx [7]

Answer:

kantut

Step-by-step explanation:

kantut kalimot hahaha you have a great day to be out of town for a few days now and then I can go to be a great day for a few days now and then I can go to be a great day for you want to be a great day to lapu lapu to get a

4 0

3 years ago

Your cell phone costs $50 a month plus $0.25 for each text message, (t). How much would your monthly bill be if you sent 40 text

aalyn [17]

Answer:

$60

Step-by-step explanation:

40 text messages × .25 each = $10. Plus the $50 per month is $60.

8 0

2 years ago

Read 2 more answers

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

(c) z = 6x ln(y)

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

3 years ago