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Amiraneli [1.4K]
3 years ago
10

Can someone please help me, this is for summer school and I need fast replies, I have 29 other question like these, please help.

​

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

\implies {\blue {\boxed {\boxed {\purple {\sf { \:  A. \:- 8 {v}^{4}  + 3 {v}^{3}  + v + 5}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 + 6v + 3 {v}^{3} ) - (5v + 8 {v}^{4}  - 1)

➼\: 4 + 6v + 3 {v}^{3}  - 5v  -  8 {v}^{4}  + 1

Combining like terms, we have

➼\: - 8 {v}^{4}  + 3 {v}^{3}  + 6v - 5v + 4 + 1

➼\:  - 8 {v}^{4}  + 3 {v}^{3}  + v + 5

<h3 />

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

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Liono4ka [1.6K]
Find and graph the feasible region for the following constraints: x + y < 5. 2x<span> + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + </span>2y<span> = 0. x - </span>2y = 0.
6 0
3 years ago
50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n
irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

Contestants remaining after first day = 50,000-10,000 = 40,000

Second day:

Contestants= 40,000

20% removed

That is (20/100)×40000=8000

Balance =40000-8000=32,000

Third day:

Contestants= 32000

20% removed

That is (20/100)×32000=6400

Balance =32000-6400=25,600

Fouth day:

Contestants= 25,600

20% removed

That is (20/100)×25,600=5,120

Balance =25,600-5,120=20,480

Fifth day:

Contestants= 20,480

20% removed

That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

20% removed

That is (20/100)×16,384=3276.8

Balance =16,384-3276.8=13,107.2

Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

6 0
3 years ago
I’m pretty confused so a 15 pointer
Bingel [31]
I don’t think f would have any value in this equation and f would represent 1 zero??
4 0
3 years ago
James has mapped his seat and his teacher's seat on the coordinate plane at (0,10) and (–4,6). Find the distance between their s
pshichka [43]

Answer:

4√2 units (Answer C).

Step-by-step explanation:

Going from the seat at (-4,6) to the one at (0,10), x increases by 4 units and y increases by 4 units.  We need to use the distance formula to determine how far apart these seats are.

d = √(change in x)^2 + (change in y)^2 ).

That works out to:

d = √(4^2 + 4^2) = √(32) = 4√2 units (Answer C).

8 0
3 years ago
Read 2 more answers
Use the diagram to answer the following questions.125°Lx2X+10NmZNPMdegreesmZLPMdegrees
lutik1710 [3]

For the angle MPN we know that is oposite to the angle QPL so the will be equal so:

\angle MPN=125º

Now with the value of MPN we can made an equation for x so:

125=2x+10

and we solve for x

\begin{gathered} 125-10=2x \\ \frac{115}{2}=x \\ 57.5=x \end{gathered}

and the angle LPM will be the complementari angle of 125 so:

\begin{gathered} \angle LPM=180-125 \\ \angle LPM=55º \end{gathered}

4 0
1 year ago
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