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saul85 [17]
3 years ago
11

The equation y=2/3x is a proportional relationship. Which value represents the constant of proportionality?

Mathematics
1 answer:
stepan [7]3 years ago
7 0

Answer:

k = \frac{2}{3}

Step-by-step explanation:

The equation of proportionality is

y = kx ← k is the constant of proportion

y = \frac{2}{3} x ← is in this form

with k = \frac{2}{3}

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Answer:

Option (1)

Step-by-step explanation:

Option (1)

3\frac{3}{9}+7\frac{6}{11}=10\frac{87}{99}

3\frac{3}{9}+7\frac{6}{11} =3+\frac{3}{9}+7+\frac{6}{11}

             =(3+7)+(\frac{3}{9}+\frac{6}{11})

             =10+(\frac{3}{9}\times \frac{11}{11})+(\frac{6}{11}\times \frac{9}{9})

             =10+(\frac{33}{99}+\frac{54}{99})

             =10+\frac{87}{99}

             =10\frac{87}{99}

True.

Option (2)

2\frac{3}{8}+6\frac{4}{5}=8\frac{12}{40}

2\frac{3}{8}+6\frac{4}{5}=2+\frac{3}{8}+6+\frac{4}{5}

             =(2+6)+(\frac{3}{8}+\frac{4}{5})

             =(8)+(\frac{3}{8}\times \frac{5}{5} +\frac{4}{5}\times \frac{8}{8})

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             =8+\frac{40}{40}+\frac{7}{40}

             =8+1+\frac{7}{40}

             =9+\frac{7}{40}

             =9\frac{7}{40}

False.

Option(3)

3\frac{3}{7}+4\frac{2}{3}=7\frac{2}{21}

3\frac{3}{7}+4\frac{2}{3}=(3+\frac{3}{7})+(4+\frac{2}{3})

             =(3+4)+(\frac{3}{7}+\frac{2}{3})

             =7+(\frac{3}{7}\times \frac{3}{3} +\frac{2}{3}\times \frac{7}{7})

             =7+(\frac{9}{21}+\frac{14}{21})

             =7+(\frac{23}{21})

             =7+(\frac{21}{21}+\frac{2}{21})

             =8+\frac{1}{21}

             =8\frac{1}{21}

False.

Option (4)

4\frac{5}{6}+5\frac{5}{7}=9\frac{10}{13}

4\frac{5}{6}+5\frac{5}{7}=4+\frac{5}{6}+5+\frac{5}{7}

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             =9+(\frac{5}{6}\times \frac{7}{7}+\frac{5}{7}\times \frac{6}{6})

             =9+(\frac{35}{42}+\frac{30}{42})

             =9+\frac{65}{42}

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             =9+1+\frac{23}{42}

             =10\frac{23}{42}

False.

Therefore, Option (1) is the answer.

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