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3 years ago

11

The equation y=2/3x is a proportional relationship. Which value represents the constant of proportionality?

1 answer:

stepan [7]3 years ago

7 0

Answer:

k = $\frac{2}{3}$

Step-by-step explanation:

The equation of proportionality is

y = kx ← k is the constant of proportion

y = $\frac{2}{3}$ x ← is in this form

with k = $\frac{2}{3}$

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Shelly has a gift card for her favorite restaurant for $15. She wants to treat a group of her friends to sandwiches at the resta

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Step-by-step explanation:

the money that Shelly will owe after buying x sandwiches and using the card will be:

if x < 4 then 15 - 4.5x <= 15 - 3*4.5 = 1.5 she will not owe anything plus she will receive change of $1.5.

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Step-by-step explanation:

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So i need help with the question below.

Shkiper50 [21]

Answer:

Option (1)

Step-by-step explanation:

Option (1)

$3\frac{3}{9}+7\frac{6}{11}=10\frac{87}{99}$

$3\frac{3}{9}+7\frac{6}{11}$ $=3+\frac{3}{9}+7+\frac{6}{11}$

$=(3+7)+(\frac{3}{9}+\frac{6}{11})$

$=10+(\frac{3}{9}\times \frac{11}{11})+(\frac{6}{11}\times \frac{9}{9})$

$=10+(\frac{33}{99}+\frac{54}{99})$

$=10+\frac{87}{99}$

$=10\frac{87}{99}$

True.

Option (2)

$2\frac{3}{8}+6\frac{4}{5}=8\frac{12}{40}$

$2\frac{3}{8}+6\frac{4}{5}=2+\frac{3}{8}+6+\frac{4}{5}$

$=(2+6)+(\frac{3}{8}+\frac{4}{5})$

$=(8)+(\frac{3}{8}\times \frac{5}{5} +\frac{4}{5}\times \frac{8}{8})$

$=8+(\frac{15}{40}+\frac{32}{40})$

$=8+\frac{47}{40}$

$=8+\frac{40}{40}+\frac{7}{40}$

$=8+1+\frac{7}{40}$

$=9+\frac{7}{40}$

$=9\frac{7}{40}$

False.

Option(3)

$3\frac{3}{7}+4\frac{2}{3}=7\frac{2}{21}$

$3\frac{3}{7}+4\frac{2}{3}=(3+\frac{3}{7})+(4+\frac{2}{3})$

$=(3+4)+(\frac{3}{7}+\frac{2}{3})$

$=7+(\frac{3}{7}\times \frac{3}{3} +\frac{2}{3}\times \frac{7}{7})$

$=7+(\frac{9}{21}+\frac{14}{21})$

$=7+(\frac{23}{21})$

$=7+(\frac{21}{21}+\frac{2}{21})$

$=8+\frac{1}{21}$

$=8\frac{1}{21}$

False.

Option (4)

$4\frac{5}{6}+5\frac{5}{7}=9\frac{10}{13}$

$4\frac{5}{6}+5\frac{5}{7}=4+\frac{5}{6}+5+\frac{5}{7}$

$=(4+5)+(\frac{5}{6}+\frac{5}{7})$

$=9+(\frac{5}{6}\times \frac{7}{7}+\frac{5}{7}\times \frac{6}{6})$

$=9+(\frac{35}{42}+\frac{30}{42})$

$=9+\frac{65}{42}$

$=9+(\frac{42}{42}+\frac{23}{42})$

$=9+1+\frac{23}{42}$

$=10\frac{23}{42}$

False.

Therefore, Option (1) is the answer.

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Answer:

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Step-by-step explanation:

The sum of numbers always terminate and ends.

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Answer:

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Step-by-step explanation:

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