Answer:

Step-by-step explanation:
![\sqrt{5}  \times  \sqrt{10}  \\  =  \sqrt{5}  \times  \sqrt[]{5}  \times  \sqrt{2}  \\   = 5\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%7B10%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%5B%5D%7B5%7D%20%20%5Ctimes%20%20%5Csqrt%7B2%7D%20%20%5C%5C%20%20%20%3D%205%5Csqrt%7B2%7D%20)
<h3>Hope it is helpful....</h3>
 
        
                    
             
        
        
        
The answer is A. for this, you have to set up a system of equations. the first one will be the area equation. since you know area=length x width, your equation will be LxW=50. the next equation is L=2W, since the length is two times the width. then, plug in 2W for the L in the other equation and you get 2W^2=50. divide by 2 and get W^2=25. square root both sides and you get W=5. plug back into the other equation to find L=10. Then, add the sides of the rectangle for the perimeter. 10+5+10+5=30.
        
             
        
        
        
Answer:
E, A, F
Step-by-step explanation:
 
        
             
        
        
        
Answer:
Red
Step-by-step explanation:
Bc if you - 8x it would be -2y=12-8x and then you divide -2 by 12 and -8x the answer would be y=4x-6