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3 years ago

Pleaseeee helpppppppppp

Mathematics

1 answer:

Georgia [21]3 years ago

3 0

Answer:

Step-by-step explanation:

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Brad buys a jacket that is on sale for 30% off the original price.The expression p - 0.3p can be used to find the sale price of

attashe74 [19]

Answer:

$56

Step-by-step explanation:

The jacket is on sales for 30% off the original price = (0.3)

The original price (P) = $80

However, the expression "p - 0.3p" is to be used to find the sales price

The sale price = p - 0.3p

The sale price = $80 - 0.3($80)

The sale price = $80 - $24

The sale price = $56

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3 years ago

Adding fractions and mixed numbers. 5 1/3+12 1/2

Viefleur [7K]

Answer:17 5/6

Step-by-step explanation:

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3 years ago

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Find the approximate area of a circle with radius equal to 8 ft. (Use = 3.14.)

Tcecarenko [31]

The area of a circle is given by

$A=\pi r^2$

If you want to approximate pi with 3.14, the formula becomes

$A = 3.14\times 8^2 = 3.14 \times 64 = 200.96$

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4 years ago

What are the steps in solving this problem?

asambeis [7]

What I see is that they are multiplying by 5 so the last one is 10 x 5 which equals 50!

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3 years ago

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Find the flux of the vector field F = 〈e-z,4z,6xy) across the curved sides of the surface S = {(x,y,z): z= cos y, lys π, 0sxs4}

Len [333]

I'll go ahead and assume you meant to say that <em>S</em> is the surface given by

$S = \left\{(x,y,z) \mid z = \cos(y)\text{ with } 0\le y\le \pi\text{ and }0\le x\le4\right\}$

This immediately gives us a parameterization for the surface,

$\vec r(x, y) = \left\langle x, y, \cos(y)\right \rangle$

The upward-pointing normal vector to this surface is then

$\vec n = \dfrac{\partial\vec r}{\partial x} \times \dfrac{\partial\vec r}{\partial y} = \left\langle0,\sin(y),1\right\rangle$

Then the flux of $\vec F(x,y,z) = \left\langle e^{-z}, 4z, 6xy\right\rangle$ across <em>S</em> is

$\displaystyle \iint_S \vec F(x,y,z)\cdot\mathrm d\vec s = \int_0^4\int_0^\pi \vec F(x,y,\cos(y))\cdot\vec n\,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi \left\langle e^{-\cos(y)},4\cos(y),6xy\right\rangle \cdot \left\langle0,\sin(y),1\right\rangle \,\mathrm dy\,\mathrm dx \\\\ = \int_0^4\int_0^\pi (4\sin(y)\cos(y)+6xy)\,\mathrm dy\,\mathrm dx \\\\ = 2 \int_0^4\int_0^\pi (\sin(2y) + 3xy)\,\mathrm dy\,\mathrm dx = \boxed{24\pi^2}$

8 0

3 years ago