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lions [1.4K]
3 years ago
9

Best answer gets Brainliest!!! CHOOSE 3!

Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

I think "A" for the first one

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In a sample of 1000 randomly, selected consumers who had opportunities to send in a rebate claim form after purchasing a product
Alexxx [7]

Answer: =(0.2232,0.2768)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

p\ \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

Given : Sample size : n=1000

The proportion of people selected consumers who had opportunities to send in a rebate claim form after purchasing a product said they never did so =\dfrac{250}{1000}=0.25

Significance level : 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Now, the 95% confidence Interval for the true proportion of such consumers who never apply for a rebate will be :-

0.25\ \pm (1.96)\sqrt{\dfrac{0.25(1-0.25)}{1000}}\\\\\approx0.25\pm0.0268\\\\=(0.2232,\ 0.2768)

Hence, a confidence Interval for the true proportion of such consumers who never apply for a rebate .

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3 years ago
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Step-by-step explanation:

3/5 is greater than 2/5, so your answer goes into the negatives

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