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VladimirAG [237]
2 years ago
6

Find arc DC pls I’m stuck on this problem

Mathematics
1 answer:
stepan [7]2 years ago
8 0

Answer:

m\overset{\Large\frown}{ABC} \: = \: 196°

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What is the variable used to predict another variable called________.A. Independent variableB. Dependent variableC. Moderating v
UkoKoshka [18]

Answer:

A. Independent variable

Step-by-step explanation:

The prediction of a variable can be done if we have the independent variable. Which is the required variable that is used to determine the value of the other variable. The variable to be predicted is dependent on the required variable.

An independent variable can also be referred to as a predictor variable. When its value is known, it can be used to obtain the dependent variable.

7 0
3 years ago
Its for science but its got math involved<br>its got to do with speed distance and time​
KIM [24]
<h3>for 1</h3>

distance:1, 1, 1.3, 1.5, 2, 2.3, 2.5, 3 ,3.2, 4

time. :1, 2, 3 , 4 , 5 , 6 , 7 , 8 ,. 9 ,10

<h3>for 2</h3>

distance:1.5, 2, 3.2, 4.2, 5, 6, 7, 8

time. : 1 , 2, 3 , 4. , 5, 6, 7, 8

<h3>at 5 seconds which travelled the greatest distance : snail 2</h3>

<h3>which travelled a greater distance:snail 2</h3>

<h3>what is the speed of snail 1 at 8 second :</h3>

distance = 3. Time = 8

speed = distanc<em>e</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>ti</em><em>me</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>spee</em><em>d</em><em> </em><em>=</em><em> </em><u>8</u>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em>

<em>sp</em><em>eed</em><em> </em><em>=</em><em>2</em><em>.</em><em>6</em><em>6</em><em> </em>

<em>approximately</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>7</em><em>. </em><em> </em><em>or</em><em> </em><em>3</em>

7 0
3 years ago
Please answer ASAP, thank you!
Mkey [24]

Answer:

1) a = 110

2) b = 65

3) c = 115 d= 65 e = 115

How I found the last one?

The whole thing equals 360.

d is equal to 65 so I added those together.

That equals 130. So i subtracted that from 360.

I got 230. Next, I divided that by 2 to get the final 2 angles.

4 0
3 years ago
Read 2 more answers
What is the moral of the story
dexar [7]
Could u please name the story? The picture isn't clear enough for me to read
3 0
3 years ago
Calcula y comprueba las ecuaciones: plisss lo necesito alguien me puede ayudar a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8
vesna_86 [32]

Answer:

a) x=3

b) z=10

c) P= 2

d) X=7

e) U=1

Step-by-step explanation:

Resolver una ecuación consiste en hallar los valores de la variable que hacen cierta la igualdad.

a) 2x= 6

El coeficiente es el número junto a la variable. En este caso, el coeficiente es 2. Para eliminar este número en la expresión 2x, debido a que la variable x esta multiplicada por 2, deberás dividir ambos lados de la ecuación entre 2, debido a que la operación opuesta de la multiplicación es la división.

(2x)÷2=6÷2

x= 3

Comprobar la solución de una ecuación se hace al remplazar la variable en una ecuación con el valor de la solución. La solución debería satisfacer la ecuación cuando se ingresa en esta.

En este caso:

2*3= 6

6=6

b) 10 + z= 20

En este caso se debe sumar o restar la constante que se encuentra acompañando a la variable en ambos lados de la ecuación de manera de aislar el término de la variable. En este caso:

10 - 10 + z= 20 -10

z= 10

Comprobación:

10 + z=20

10 + 10=20

20=20

c) P + 9= 11

P +9 - 9= 11 -9

P=2

Comprobación:

2 + 9= 11

11=11

d) 3X + 8 = 29

En este caso, se suma o resta la constante en ambos lados de la ecuación y luego se elimina el coeficiente de la variable mediante la división o multiplicación. Esto es:

3X + 8 - 8= 29 - 8

3X= 21

3X ÷3= 21÷3

X=7

Comprobación:

3*7 + 8=29

21+8=29

29=29

e) 2U + 8= 10

2U + 8 - 8= 10 -8

2U= 2

2U ÷2= 2÷2

U=1

Comprobación:

2*1 + 8= 10

2 + 8= 10

10=10

8 0
2 years ago
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