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Setler [38]
3 years ago
9

Its for science but its got math involvedits got to do with speed distance and time​

Mathematics
1 answer:
KIM [24]3 years ago
7 0
<h3>for 1</h3>

distance:1, 1, 1.3, 1.5, 2, 2.3, 2.5, 3 ,3.2, 4

time. :1, 2, 3 , 4 , 5 , 6 , 7 , 8 ,. 9 ,10

<h3>for 2</h3>

distance:1.5, 2, 3.2, 4.2, 5, 6, 7, 8

time. : 1 , 2, 3 , 4. , 5, 6, 7, 8

<h3>at 5 seconds which travelled the greatest distance : snail 2</h3>

<h3>which travelled a greater distance:snail 2</h3>

<h3>what is the speed of snail 1 at 8 second :</h3>

distance = 3. Time = 8

speed = distanc<em>e</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>ti</em><em>me</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>spee</em><em>d</em><em> </em><em>=</em><em> </em><u>8</u>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em>

<em>sp</em><em>eed</em><em> </em><em>=</em><em>2</em><em>.</em><em>6</em><em>6</em><em> </em>

<em>approximately</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>7</em><em>. </em><em> </em><em>or</em><em> </em><em>3</em>

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Find an equation of variation in which y varies inversely as x and y=5 and x=21. Then find the value of y when x=10.
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Answer:

see explanation

Step-by-step explanation:

Given that y varies inversely as x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = 5 , x = 21

k = yx = 5 × 21 = 105

y = \frac{105}{x} ← equation of variation

When x = 10, then

y = \frac{105}{10} = 10.5

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