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3 years ago

Please answer ASAP, thank you!

Mathematics

2 answers:

Mkey [24]3 years ago

4 0

Answer:

1) a = 110

2) b = 65

3) c = 115 d= 65 e = 115

How I found the last one?

The whole thing equals 360.

d is equal to 65 so I added those together.

That equals 130. So i subtracted that from 360.

I got 230. Next, I divided that by 2 to get the final 2 angles.

Sveta_85 [38]3 years ago

3 0

Answer:

a. a and 70º are Supplementary angles (add up to 180º)

Therefore, $a + 70\º = 180\º \Rightarrow a=110\º$

b. a and 25º are Complementary angles (add up to 90º)

Therefore, $a + 25\º = 90\º \Rightarrow a=65\º$

c. c and 65º are Supplementary angles (add up to 180º)

Therefore, $c + 65\º = 180\º \Rightarrow c=115\º$

d and 65º are opposite angles, therefore $d=65\º$

c and e are opposite angles, once $c=115\º$ , $e=115\º$ as well.

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Read 2 more answers

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

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a. What is the probability that exactly 2 of them have never been married?

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At x = 2

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b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

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