Container A:
y=-6x+800
800 is y intercept( it already have 800 before leaking)
leaking means that its went down so it had to be negative -6x)
container B:
y=-10x+1000
same thing with a container B
-6x+800=-10x+1000 = 800-6x=1000-10x

6 0

3 years ago

What is the missing step in the given proof? Help me out with my math homework please!

kari74 [83]

Answer: The missing step is,

m∠OCP ≅ m∠ABC because corresponding angles made by the same transversal on the parallel lines are congruent.

Step-by-step explanation:

Given : $AC \parallel BD$ , $AB \parallel CD$

And, $AC \perp CD$

We have to Prove : Angle PCQ is complementary to angle ABC

⇒ $m\angle PCQ + m\angle ABC = 90^{\circ}$

Proof: Since, $AC \perp CD$

⇒ $m\angle OCQ = 90^{\circ}$

But, $m\angle OCQ = m\angle OCP +m\angle PCQ$ ( By angle addition postulate )

⇒ $m\angle OCP +m\angle PCQ = 90^{\circ}$ ( By transitive property of equality )

Since, $AC \parallel BD$ ,

⇒ $\angle OCP\cong \angle ABC$ ( corresponding angles made by the same transversal are congruent)

⇒ $m\angle OCP = m\angle ABC$ ( By the definition of congruent angles )

This leads,

$m\angle ABC +m\angle PCQ = 90^{\circ}$ ( by the transitive property of equality )

Thus, by the definition of complementary angles,

Angle PCQ is complementary to angle ABC

Hence proved.

5 0

3 years ago

Read 2 more answers