3 years ago

PLEASE HELP!! DUE SOON!!

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

Answer: Its A. decagon

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Answer:

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Part 2)

Part 3) $< I=28.07\°$

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Step-by-step explanation:

Part 1) Find the measure of side HI

Applying the Pythagoras Theorem

$GI^{2} =GH^{2}+HI^{2}$

substitute the values and solve for HI

$17^{2} =8^{2}+HI^{2}$

$HI^{2}=17^{2}-8^{2}$

$HI^{2}=225$

$HI=15\ units$

Part 2) Find the measure of angle G

In the right triangle GHI

$cos(G)=\frac{GH}{GI}$

substitute the values

$cos(G)=\frac{8}{17}$

$G=arccos(\frac{8}{17})=61.93\°$

Part 3) Find the measure of angle I

Remember that

The sum of the interior angles of a triangle must be equal to 180 degrees

substitute the values

$61.93\°+90\°+< I=180\°$

$< I=180\°-(61.93\°+90\°)=28.07\°$

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