<span>A gallon of water weighs 8 1/3 lb
</span><span>1 1/5 gallon....................? lbs
</span>8 1/3 * 1 1/5
= 25/3 * 6/5
= 10
answer : <span>1 1/5 gallon of water weighs 10 lbs</span>
Answer: The first outcome shall be 0.33 or 33%.
The second outcome would be 0.5 or 50%
Step-by-step explanation: The bag contains exactly one yellow, one red and one green marble. So when he draws the first marble the sample space shall be the total possible outcomes, which is three, since he has three (3) marbles altogether. When he draws the first time without looking, all three marbles have an equal probability of being picked which can be derived thus;
P(Red) = Number of required possibilities/Number of all possibilities
P(Red) = 1/3
P(Red) = 0.33
Note that there is only one marble of each color which means P(Yellow) and P(Green) is also 0.33 respectively.
After choosing the first marble, without replacing the first one he now chooses another marble. The sample size would have reduced to 2 (since one marble has been drawn). Hence, the outcome when he draw a second marble can be calculated as follows;
P(Red) = Number of required outcomes/Number of possible outcomes
P(Red) = 1/2
P(Red) = 0.5
Answer:
14.2 years
Step-by-step explanation:
The multiplier of the population each year is 1 +5% = 1.05, so after n years the population has been multiplied by 1.05^n. You want to find the value of n that makes this expression equal to 2:
2 = 1.05^n
log(2) = n·log(1.05) . . . . . take logarithms
log(2)/log(1.05) = n ≈ 14.2
Growing at a rate of 5% per year, it will take about 14.2 years for the population to double.
Answer:
375 girls
Step-by-step explanation:
Let the number of girls in the school be y.
Then, we can write the equation:
We can now solve for y by multiplying both sides by
Therefore there are 375 girls in the school.
Answer:
The answer is
<h2>
</h2>
Step-by-step explanation:
First of all find the LCM of the denominators
The LCM of 5 and 56 is 280
So we have
<h3>
</h3>
Reduce the fraction with 4
We have the final answer as
<h3>
</h3>
Hope this helps you
