F(x)=(4x-3)^-1(10))
(-4x+3(10))
(-4x(30))
i think that's how you would solve it i can't quite remember if you substitute the x with the 10 but if you do it would be
f(x)=4(10)-3
40-3
37
but im pretty sure it's the first way.
Let the smaller angle be x.
smaller = x
larger = 3x
known angle = 65°
All angles add up t10 180:
x + 3x + 65 = 180
4x + 65 = 180
4x = 115
x = 28.75
Smaller angle = 28.75
Larger angle = 86.25
Answer: The angles are 28.75° and 86.25°
Answer:
2b^2
Step-by-step explanation:
according to the question equation is
(a^2 + b^2 ) - (a^2 - b^2)
a^2 + b^2 - a^2 + b^2
plus a square and minus a square gets cancel
b^2 + b^2
since they are like terms they can be added
2b^2
