3 years ago

Find the minimum value of

1 answer:

8 0

Answer:

Find the minimum and maximum values of the objective function subject to the given constrants. Objective function: C= 2x + 3y

Constraints:

x>0

y>0

Comment: These two conditions tell you the answers are in the 1st Quadrant.

-----------------------------

x +y < 9

Graph the boundary line: y = -x+9

Solutions points are below the boundary line and in the 1st Quadrant.

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What are the constants in this expression? -10.6+9/10+2/5m-2.4n+3m

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Answer:

-10.6 and ⁹/₁₀

Step-by-step explanation:

The constants are the numbers that stand by themselves: -10.6 and ⁹/₁₀.

The <em>variables</em> are m and n.

The <em>coefficients</em> are the numbers in front of the variables: ⅖, 2.4, and 3.

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Answer: Its factored form will be

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Step-by-step explanation:

Since we have given that

$6n^4-24n^3+18n$

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$6n(n^3-4n^2+3)$

Now,

$\text{Let }p(n)=n^3-4n^2+3$

Now, by hit and trial method, we put n=1,

$p(1)=1^3-4\times1^2+3=1-4+3=1-1=0$

$n=1\\n-1=0$

So, n-1 is also factor of p(n).

Now,

$\frac{n^3-4n^2+3}{n-1}=n^2-3n-3$

So, its factored form will be

$6n(n-1)(n^2-3n-3)$

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