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Anastasy [175]
3 years ago
12

Find the minimum value of

Mathematics
1 answer:
viva [34]3 years ago
8 0

Answer:

Find the minimum and maximum values of the objective function subject to the given constrants. Objective function: C= 2x + 3y

Constraints:

x>0

y>0

Comment: These two conditions tell you the answers are in the 1st Quadrant.

-----------------------------

x +y < 9

Graph the boundary line: y = -x+9

Solutions points are below the boundary line and in the 1st Quadrant.

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Write an equation of the line passing through the point (3, 4) that is parallel to the line −2x+3y=2
mote1985 [20]

Parallel lines have same slope, so first isolate y to get the equation into y=mx+b form.

-2x+3y=2

3y = 2x + 2

y = \frac{2x+2}{3}

Now plug the point (3,4) into y = 2x + b

4 = 2(3) + b

Solves for be

b = -2

So the new equation is y = 2x - 2

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Can I get help on this bc if I don’t do it now my math teacher will call my parents
kherson [118]

Answer:

<u>39.28cm^2 </u>

Step-by-step explanation:

Simple work out the area of a circle and halve it.

3.142xr^2

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7 0
3 years ago
The temperature was -7 degrees in the morning. By noon, it was 12 degrees outside. What was the change in temperature?
11111nata11111 [884]

Answer:

19 degrees

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6 0
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The areas of two similar octagons are 112 in.2 and 63 in.2. What is the ratio (larger to smaller) of their perimeters?
Eddi Din [679]
Might be late but since the area is a squared unit (m^2), it's 2-dimensional perimeter is just a plain unit(m), it's 1-dimensional the 2-dimensional ratio is 112/63 Then, the 1-dimensional ratio is sqrt(112/63), which is 4/3. Plus i just took the quiz and got that question right :)

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