2 years ago

PLEASE HELP ME!!! What is the answer to 6x^2-4x+10=0 using quadratic formula

Mathematics

1 answer:

densk [106]2 years ago

5 0

Answer:

= − 56

Step-by-step explanation:

:D If you want me to explain it I can

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In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

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Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

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$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

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Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

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