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2 years ago

11

In Gwinnett, the sales tax is 6%. You buy a watch that costs $45.50. What is the TOTAL cost including tax?.

1 answer:

CaHeK987 [17]2 years ago

5 0

Answer: $48.23

Step-by-step explanation: %6 is equal to 0.06 so you can multiply the price of the watch by 1.06 because that is the base price plus the sales tax. That gets you $48.23

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A cylindrical Is half full of oil The cylinder Has a base radius of 100 cm The height of the cylinder 250cm 1 litres = 1000cm3 H

Softa [21]

Answer:

V=3926.99 liters

Step-by-step explanation:

cylindrical Is half full of oil The cylinder Has a base radius of 100 cm The height of the cylinder 250cm 1 litres = 1000cm3 How many litres of oil are in the tank?

Volume of a cylinder can be calculated using below formula

V=π r^2 h

Where r= radius

h= height

radius = 100 cm

h=250cm

But the cylinder is half filled, then the formula becomes

V=(π r^2 h) × 1/2

Then substitute the values we have

V=( π × 100^2 ×250) × 1/2

V=3926990 cm^3

But 1 litres = 1000cm3

Then V=(3926990 cm^3)/ 1000

V=3926.99 liters

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3 years ago

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pentagon [3]

Step-by-step explanation:

Take a look at the picture, And tell me if am wrong

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3 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

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Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

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= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

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= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

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3 years ago

Solve the formula d = rt for t. A. t = rd B. t = d – r C. t = D. t =

tekilochka [14]

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3 0

3 years ago

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damaskus [11]

Answer:

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Step-by-step explanation:

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3 years ago

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