All categories

3 years ago

Gerry is shopping for clothes at the mall.He buys 4 new shirts for $6.00.What is the unit rate for the shirts

Mathematics

2 answers:

elena-s [515]3 years ago

5 0

the unit rate is 4:6

9966 [12]3 years ago

5 0

The unit rate is $1.50 per shirt.

To find this, divide 6$ by 4 shirts to get 1.5

You might be interested in

David measures how many inches his tomato plant grows every week. What is the independent variable?

Norma-Jean [14]

Answer:

It is tomato plant

Step-by-step explanation:

- The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable. - - - The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

7 0

3 years ago

1/2 of 30= 1/4 of [ ]

MaRussiya [10]

Answer:

Step-by-step explanation:

half of 30 is 15

and 15 is 1 quarter of 60

7 0

3 years ago

Answer this quick I have 20 minutes<br> 25 points

e-lub [12.9K]

The answer is A. You can comment if u want an explanation :)

6 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago

Factor. 21x^2 -32x+12

baherus [9]

Through trial and error:
(7x-6)(3x-2)

Usually it works best to test out a number of possibilities :)

3 0

3 years ago