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Tom [10]
3 years ago
7

Gerry is shopping for clothes at the mall.He buys 4 new shirts for $6.00.What is the unit rate for the shirts

Mathematics
2 answers:
elena-s [515]3 years ago
5 0

the unit rate is 4:6

9966 [12]3 years ago
5 0
The unit rate is $1.50 per shirt.

To find this, divide 6$ by 4 shirts to get 1.5
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Help!! Picking Brainliest! I need an answer fast...
IRISSAK [1]

3 * 5 = 15 miles during weekdays

6.5*2 = 13 miles on weekends

13 +15 = 28 miles total


28 / 7  = 4 miles average per day

6 0
3 years ago
-6p - 20 = -2p +4(1 - 3p)
kirza4 [7]

Answer:

p = 3

Hope this helps

7 0
3 years ago
Read 2 more answers
Marissa is painting one of her bedroom walls. She marks off 1/4 of the wall. Then she divides the marked section into 3 equal pa
Sergio039 [100]

Answer:

1/12

Step-by-step explanation:

The question can be written as (1/4) / 3. This is equivalent to (1/4)*(1/3), which is 1/12.

4 0
3 years ago
Mathematics Areas and perimeters ​
sweet-ann [11.9K]

Answer:

54.5 Sq. cm

Step-by-step explanation:

<em>area of a right angled triangle = 1/ 2 × base × height </em>

(here, the base is 8 and height is 6)

= 1/ 2 × 6 × 8

= 4 × 6

<u>= 24 Sq. cm</u>

<em>area of a circle</em> = \pi r²

(r is the radius that is diameter/ 2, and the value of \pi is 3. 14)

  • r = 10/ 2 = 5 cm

= 3. 14.× (5)²

= 3.14 × 25

<u>= 78.5 Sq. cm</u>

area of the shaded region = area of Circle - area of triangle

= 78.5 - 24

<h3>= 54.5 Sq. cm</h3>

that is option 3

7 0
2 years ago
The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser
Liono4ka [1.6K]
The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

z-score= \frac{X-Mean}{Standard Deviation}
z-score= \frac{405.5-402.7}{8.8} =0.32

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)

from  the z-table, the reading P(Z\ \textless \ 0.32) gives 0.6255

hence, 
P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0
3 years ago
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