Answer:
2
Step-by-step explanation:
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2 answers:
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The coordinates of point B' are (-3, 6).
<h2>Given that</h2>Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
<h3>We have to determine</h3>What are the coordinates of B' after the translation?
<h3>According to the question</h3>Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.
After the given transformation the coordinates of point B' would be:
Therefore, the coordinates of point B' are (-3, 6).
To know more about Transformation click the link given below.
Answer: The graph in the bottom right-hand corner
(see figure 4 in the attached images below)
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Explanation:
Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.
Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.
After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.
