(√0,04-√(-1,2)²+√121)×√81

Mathematics

1 answer:

Semenov [28]2 years ago

6 0

Answer: 90

Step-by-step explanation:

$\displaystyle\ \Large \boldsymbol{} (\sqrt{0,04}-\sqrt{(-1,2)^2}+\sqrt{121 } ) \cdot \sqrt{81} = \\\\\\(0,2-1,2+11)\cdot 9=(11-1)\cdot 9=90$

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