Question

(√0,04-√(-1,2)²+√121)×√81

Answer 1

Answer:  90

Step-by-step explanation:

$\displaystyle\ \Large \boldsymbol{} (\sqrt{0,04}-\sqrt{(-1,2)^2}+\sqrt{121 } ) \cdot \sqrt{81} = \\\\\\(0,2-1,2+11)\cdot 9=(11-1)\cdot 9=90$