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2 years ago

A database contains 58,000 items. Items are added to the database at a rate of 2 items per minute.

Mathematics

1 answer:

Lelechka [254]2 years ago

5 0

Answer:

Your answer is

2 times per min So Function.....

f(x)=n= 2x

where n= items

x= min

Hope that this is helpful. Tap the crown button, Mark my answer as............. BRAINLIST......... Like & Follow me to get more answer.

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can someone please help me, Ive missed a few days of school after christmas break, and I can't seem to remember half of the thin

vodka [1.7K]

Answer:

The correct answer for this question would be <u>y=3x</u>

Step-by-step explanation:

If you look on the graph included in the picture you provided, you can see that all the numerical values in the 'y' row are three times the value of the values in the 'x' row.

Brainliest appreciated!

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2 years ago

Please help I will give brainliest!

Burka [1]

Answer: the statement “measure of <4 is 105 degrees” is incorrect.

Explanation: This is because since both angles 1 and 3 are vertical, this means they are both 95. This gives us 190 (95x2). Now we subtract this from 360 which gives us 170. Since angles 2 and 4 are vertical, we divide by 2, which gives us 85, not 105.

Hope this helps! :)

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2 years ago

You are considering a certain telephone company. They charge $0.17 per minute of talking, plus a fixed base monthly fee of $40 .

brilliants [131]

Answer:

C = 40 + 0.17M

Step-by-step explanation:

Total monthly charge = Fixed base fee + charge per minute*total number of minutes

C = 40 + 0.17*M

C = 40 + 0.17M

8 0

3 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

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3 years ago

Find the Area and Perimeter of both figures!

Leokris [45]

where is the figures to solve.

4 0

2 years ago