Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
18
Hope this helps :) Please mark this brainiest?
Step-by-step explanation:
18/6=3
54/3=18
X = y
y = 4
By the substitution property, we can replace y with 4 in that first equation.
x = 4
Answer:
-7x + 5
Step-by-step explanation:
2(4x + 1) - 3(5x - 1)
8x + 2 - 3(5x-1)
8x + 2 - 15x + 3
8x + 5 - 15x
-7x + 5
Hope it helped !
Adriel
Answer:
-151
Step-by-step explanation:
first find the value of g(6)
g(6) = -3 × 6 - 8 ➡-24
then put this value fir f(g(6))
f(-24) = 6 × -24 -7 ➡ -151