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3 years ago

Write a linear equation in point-slope form to model the situation below:

Mathematics

1 answer:

Lilit [14]3 years ago

3 0

Answer:

y - 14.95 = 18.075(x-1)

Step-by-step explanation:

If an internet company charges $14.95 per month and a setup fee, then we can say

1 month = $14.95

If the total cost for 9 months is $159.55

Then we can write both cases as a coordinate (1, 14.95) and (9,159.55)

The equation of a line in point slope form is expresses as

y-y0 = m(x-x0)

Find the slope m

m = 159.55-14.95/9-1

m = 144.6/8

m = 18.075

Substitute m = 18.075 and any of the coordinate in the equation to have;

Using the coordinate (1, 14.95)

y - 14.95 = 18.075(x-1)

Hence a linear equation in point-slope form that model the situation is y - 14.95 = 18.075(x-1)

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3 years ago

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3 years ago

Convert 1/15 into a decimal correct to 2 decimal places

Citrus2011 [14]

Answer:

$\frac{1}{15} = 0.\overline{66}$

Step-by-step explanation:

We proceed to show the procedure to calculate the given fraction into a decimal form:

1) Since numerator is less than denominator, the integer component of the decimal number is zero:

$\frac{1}{15} = 0.xx$

2) We multiply the numerator by 10 and find the tenth digit:

$\frac{10}{15} = 0$

Then,

$\frac{1}{15} = 0.0xx$

3) We multiply the fraction in 2) by 10 and find the hundredth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.66x$

And the remainder is:

$r = 100-15\times 6$

$r = 10$

4) We multiply the remainder by 10 and divide this result by the denominator to determine the thousandth digit:

$\frac{100}{15} = 6$

Then,

$\frac{1}{15} = 0.666$

This question asks us to write a decimal correct to 2 decimal places, which has the characteristic that is infinite periodical decimal. Then, the result correct to 2 decimal places is:

$\frac{1}{15} = 0.\overline{66}$

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2 years ago

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gayaneshka [121]

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3 years ago

The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students

Delicious77 [7]

Answer:

The percentage of the students scored higher than 89% is 15.87%

Step-by-step explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84

$\mu=84$

a standard deviation of 5

so,

$\sigma=5$

we have

x=89

now, we can use z-score formula

$z=\frac{x-\mu}{\sigma}$

now, we can plug values

$z=\frac{89-84}{5}$

$z=1$

now, we can use calculator

and we get

$p(z>1)=0.1587$

So,

The percentage of the students scored higher than 89% is 15.87%

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3 years ago