Answer:
The answer would be HFG = KIJ (A)
If we know that the opposite and the adjacent side of the triangle are congruent, then the hypotenuse is congruent too. Therefor, A is correct as we know the opposite side and the adjacent side are congruent.
Answer:
1.
Mathematical concept that expresses an amount in relation to the computer unit; results from counting the elements that make up a set.
"Cardinal number"
2.
A graphic sign or set of graphic signs that expresses or represents that amount.
Step-by-step explanation:
The smallest amount of material needed is 54 square centimeters
<h3>How to determine the amount of material needed?</h3>
The given parameters are:
Volume = 36 cubic centimeters
Represent length with x, width with y and height with z.
So, we have
x = 3y
The volume is calculated as:
V = xyz
This gives
V = 3y²z
Substitute 36 for V
3y²z = 36
Divide by 3
y²z = 12
Make z the subject
z = 12/y²
The surface area is:
S = 2(xy + xz + yz)
This gives
S = 2(3y² + 3yz + yz)
Evaluate the like terms
S = 2(3y² + 4yz)
Expand
S = 6y² + 8yz
Substitute z = 12/y²
S = 6y² + 8y * 12/y²
This gives
S = 6y² + 96/y
Differentiate
S' = 12y - 96/y²
Set to 0
12y - 96/y² = 0
Multiply through by y²
12y³ - 96 = 0
Add 96 to both sides
12y³ = 96
Divide by 12
y³ = 8
Take the cube root of both sides
y = 2
Recall that:
x = 3y and z = 12/y²
This gives
x = 3 * 2 = 6
z = 12/2² = 3
Recall that:
S = 2(xy + xz + yz)
So, we have:
S = 2(6 * 2 + 3 * 3 + 2 * 3)
Evaluate
S = 54
Hence, the smallest amount of material needed is 54 square centimeters
Read more about surface areas at:
brainly.com/question/76387
#SPJ1
Answer:
-50
Explanation:
I don't really know why, but I answered a guess and got it correct, so If you trust me and what I am saying you will get the correct answer. However, If you don't trust me I completely understand why, but hope you use my answer anyway. Hope this can help you. If it doesn't please forgive me and the website I used.
Answer:
D. (-1,-2)
Step-by-step explanation:
Every number in the third quadrant of the coordinate plane has negative x and y-coordinates.
- Quadrant 1 - (x, y)
- Quadrant 2 - (-x, y)
- Quadrant 3 (-x, -y)
- Quadrant 4 (x, -y)
