Both sides are the same so they are equal so...
4x+13=5x-15
x=28
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Answer:
31/40
Step-by-step explanation:
13/40 + 18/40
Answer:
p = 2 or p = -2 4/9
Step-by-step explanation:
We can substitute x=3/2 into the equation and solve for the values of p that make the result be zero.
p^2(3/2)^2 -12(3/2) +p +7 = 0
9/4p^2 -18 + p + 7 = 0 . . . . eliminate parentheses
9p^2 +4p -44 = 0 . . . . . . simplify and multiply by 4
(9p +22)(p -2) = 0 . . . . . factor
Values of p that make 3/2 be one of the zeros are ...
p = -22/9, p = 2
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<em>Additional comment</em>
The <em>zero product rule</em> tells you a product will be zero if and only if a factor is zero. Hence the solutions to the quadratic are values of p that make the factors zero.
9p +22 = 0 ⇒ 9p = -22 ⇒ p = -22/9
p -2 = 0 ⇒ p = 2
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For p=2, the solution 3/2 has multiplicity 2. For p=-22/9, the other zero is x=123/242.
<h2>Alex accidentally forgot to stock up on toilet paper before the stay-at-home order. Now he has to buy toilet paper on the black market. Though the price of toilet paper on the black market has mostly stabilized, it still varies from day to day. The daily price of a generic brand 12-pack, X, and the daily price of a generic brand 6-pack, Y, (in rubles) jointly follow a bivariate normal distribution with:
</h2><h2>μx = 2,470, σx = 30, μy = 1,250, σ = 25, p = 0.60.
</h2><h2>(a) What is the probability that 2 (two) 6-packs cost more than 1 (one) 12-pack? (b) To ensure that he will not be without toilet paper ever again, Alex buys 7 (seven) 12-packs and 18 (eighteen) 6-packs. What is the probability that he paid more than 40,000 rubles?
</h2><h2>(c) Suppose that today's price of a 12-pack is 2,460 rubles. What is the probability that a 6-pack costs less than 1,234 rubles today? [1 US dollar is approximately 75 rubles ]</h2>
