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anyanavicka [17]
3 years ago
7

How do you simplify x^2-4x-21 divided by x+3

Mathematics
1 answer:
Xelga [282]3 years ago
6 0
We can factor x^2-4x-21 to get (x+3)(x-7)

Notice how 
3 plus -7 = -4
3 times -7 = -21
which helps us factor the trinomial

After you've factored it, we can cancel out a pair of (x+3) terms leaving us with the final answer of x-7

Note: the cancellation happens because (x+3)/(x+3) = 1. Divide anything (except 0) over itself and you'll get 1. A simpler example of this is 5/5 = 1.
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Expression: 8/3 = g/3

Denominators are same, so cancel them from each other.

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Hope this helps!
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postnew [5]

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Step-by-step explanation:

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A sequence can be generated by using an = an-1 + 4, where a1 = 6 and n is a whole number greater than 1. What are the first four
Firlakuza [10]

<u>Answer:</u>

  • The first four terms are <u>4</u><u>,</u><u>8</u><u>,</u><u>1</u><u>2</u><u>,</u><u>1</u><u>6</u>

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The given relation between the nth term and it's previous term is given by:

\boxed{an = an - 1 + 4}

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Now, Fourth term:

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