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Identify the maximum or minimum value, domain, and range of the graph of the quadratic function.

Virty [35]

Answer:

See below ~

Step-by-step explanation:

Details of the graph of the quadratic equation

Minimum value = -1
Domain : all real numbers
Range : y ≥ -1

5 0

2 years ago

Find the volume of this object.

Tems11 [23]

Answer:

408 cm^3

Step-by-step explanation:

You have to find the volume of each object individually. You first find the volume of the sphere, so you input the radius, which is 3, into the equation which comes out to be 108 cm^3. You then have to find the volume of the cylinder, and since you have the diameter of the cylinder, and you need the radius, and the radius is half of the diameter, you would input 5 into the equation as the radius, since half of 10 is 5. That comes out to be 300 cm^3, so then you add the two volumes together, which is 408 cm^3

7 0

1 year ago

A $220 tablet is on sale at half price for $110. You have a coupon for 20% off the sale price. If you use your coupon to buy the

Nitella [24]

20% is what you won't pay therefore 80% is what you'll pay.=80/100*220=$176

8 0

2 years ago

Help Por favor! Will mark brainliest!

postnew [5]

Answer: An adult’s ticket costs $9 while a children’s ticket costs $5.

Step-by-step explanation:

1). 2x + 3y = 33

2). 5x + 2y = 55

3). I’m going to use substitution.

Isolate a variable (x):

2x + 3y = 33

2x = -3y + 33

X = (-3y + 33)/2

X = -3/2y + 33/2

Substitute and solve for y:

5x + 2y = 55

5(-3/2y + 33/2) + 2y = 55

-15/2y + 165/2 + 2y = 55

-11/2y = -55/2

Y = 5 <— children’s ticket.

Solve for x:

2x + 3y = 33

2x + 3(5) = 33

2x + 15 = 33

2x = 18

X = 9 <— adult’s ticket.

Check:

5x + 2y = 55

5(9) + 2(5) = 55

45 + 10 = 55

55 = 55

2x + 3y = 33

2(9) + 3(5) = 33

18 + 15 = 33

33 = 33

8 0

3 years ago

Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure

Marina CMI [18]

Answer:

a) $P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

b) $P(0.11 < \bar X < 0.13)$

And we can use the z score defined by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And using the limits we got:

$z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22$

$z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22$

And we want to find this probability:

$P(-2.22< Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.12,0.009)$

Where $\mu=0.12$ and $\sigma=0.009$

We are interested on this probability

$P(0.11$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(0.11$

And we can find this probability with this difference and with the normal standard table or excel:

$P(-1.11$

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by: