Answer: option c
length = 9m
Perimeter = 26.4m
Step-by-step explanation:
A rectangle has a width of 4.2 m and an area of 37.8 m^2
We want yo determine the length of the rectangle and the perimeter of the rectangle.
The perimeter of the rectangle is the distance round the shape. Let the width of the triangle be w.
The perimeter of the rectangle would be expressed as Length + width + length + width. This becomes
2(length +width). So the perimeter of the given rectangle is
2(length + 4.2) but the area is given as 37.8 m^2. Area of a rectangle is length × width. It becomes
37.8= length × 4.2
Length = 37.8/4.2 = 9m
Therefore, the perimeter is
2(length + 4.2) = 2(9+4.2)
Perimeter = 2× 13.2 = 26.4m
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.




Weights of at least 340.1 are in the highest 20%.
ABCD is a square . if the coordinates of three of its vertices are A(-1,2a), B(a,2a), C(a,0), find the coordinates of D. BC is obviously 2a (it's a vertical line) then AB must be 2a (notice AB is horizontal) so BC = AC because it is a square 2a = a+1 a=1
Answer:
Option D
Step-by-step explanation:

For F=77°F
