The second leftover expression is not o(a+b). It is 6(a + b). I have attached the correct question to depict that.
Answer:
The equivalent expressions are;
8a + 2 and 6a + 6b
Step-by-step explanation:
The two leftover expressions are given as;
2(4x + 1) and 6(a + b)
In algebra, equivalent expressions are simply those expressions which when simplified, give the same resulting expression as the initial one.
Thus simply means expanding or collecting like times to make it clearer.
Now, in our question, like terms have already been collected. This means that to find an equivalent expression, we will just expand the bracket.
Thus;
2(4x + 1) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
8x + 2
Similarly,
6(a + b) will be expanded by using the 2 outside the bracket to multiply the terms inside the bracket. This gives;
6a + 6b
Thus;
The equivalent expressions are;
8a + 2 and 6a + 6b
The formula to find the amount is
here A is amount
P is the principal
'r' is the rate of interest
n is the number of years.
Case 1.
Stevan invests
P =$ 20,000
r = 3% = 0.03
n = 10 years
Hence the interest earned
= A - P = 26878.33 - 20000 = $6878.33
Case 2.
Evan invests
P = $10,000
r = 7% = 0.07
n = 7 years
Hence the interest earned
= A - P = 16057.81 - 10000 = 6057.81
Difference in the interest = 6878.33 - 6057.81 = $820.52
Rounded to the nearest dollar difference in interest = $821
Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
Answer:
answer in the pic
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)