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3 years ago

Which expression means the same as "subtract 3 from 7 and then multiply by

Mathematics

2 answers:

FrozenT [24]3 years ago

7 0

Answer:

4 x (7 - 3)

Step-by-step explanation:

So you take away 3 from the sum of which you got from 7x4

babymother [125]3 years ago

4 0

Answer:

4 x (7 - 3) is the correct option

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Jessica is measuring two line segments. The first line segment is 30 centimeters long. The second line segment is 500 millimeter

Zolol [24]

Answer:

800 mm or 80 cm

Step-by-step explanation:

We are given that Jessica is measuring two line segments.

Length of first line segment =30 cm

Length of second line segment=300 mm

We have to find that Length of two line segments together

We know that 1 cm =10 mm

Length of firs line segment =

Length of two line segments together=500+300=800 mm=

Hence, the length of two line segments together=800 mm=80 cm

Read more on Brainly.com - brainly.com/question/544258#readmore

8 0

3 years ago

Albert bought 3 blank tapes for $5.95. Find the cost per tape to the nearest cent.

Brilliant_brown [7]

Answer:

17.85

Step-by-step explanation:

just times 5.95 by 3

4 0

3 years ago

A car uses a litre of petrol to travel 4km. How many litres will it use to travel 32 kilometres.

lesya [120]

Given that,

A car uses a litre of petrol to travel 4 km.

To find,

How many litres will it use to travel 32 kilometres.

Solution,

We have,

1 litre = 4 km

1 km = (1/4) litre

Let it will use x litres to travel 32 km.

32 km = (32/4) litres

= 8 litres

Hence, 8 litres it will use to travel 32 km.

3 0

3 years ago

The graphs of the polar curves r = 4 and r = 3 + 2cosθ are shown in the figure above. The curves intersect at θ = π/3 and θ = 5π

Gennadij [26K]

(a)

$\displaystyle \frac{1}{2} \cdot \int_{\frac{\pi}{3}}^{\frac{5\pi}{3}} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

or, via symmetry

$\displaystyle\frac{1}{2} \cdot 2 \int_{\frac{\pi}{3}}^{\pi} \left(4^2 - (3 + 2\cos\theta)^2 \right) \, d\theta$

____________

(b)

By the chain rule:

$\displaystyle \frac{dy}{dx} = \frac{ dy/ d\theta}{ dx/ d\theta}$

For polar coordinates, x = rcosθ and y = rsinθ. Since
r = 3 + 2cosθ, it follows that

$x = (3 + 2\cos\theta) \cos \theta \\ 
y = (3 + 2\cos\theta) \sin \theta$

Differentiating with respect to theta

$\begin{aligned}
\displaystyle \frac{dy}{dx} &= \frac{ dy/ d\theta}{ dx/ d\theta} \\
&= \frac{(3 + 2\cos\theta)(\cos\theta) + (-2\sin\theta)(\sin\theta)}{(3 + 2\cos\theta)(-\sin\theta) + (-2\sin\theta)(\cos\theta)} \\ \\
\left.\frac{dy}{dx}\right_{\theta = \frac{\pi}{2}}
&= 2/3
\end{aligned}$

2/3 is the slope

____________

(c)

"distance between the particle and the origin increases at a constant rate of 3 units per second" implies dr/dt = 3

Angle θ and r are related via r = 3 + 2cosθ, so implicitly differentiating with respect to time

 $\displaystyle\frac{dr}{dt} = -2\sin\theta \frac{d\theta}{dt} \quad \stackrel{\theta = \pi/3}{\implies} \quad 3 = -2\left( \frac{\sqrt{3}}{2}}\right) \frac{d\theta}{dt} \implies \\ \\ \frac{d\theta}{dt} = -\sqrt{3} \text{ radians per second}$

5 0

3 years ago

Hellllllpppppppp meeeeeeeeeeeeeee

Nitella [24]

Answer:

im not good at this but would it be answer c?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers