Answer No 1:
The set up of the punnet square is shown in the attached diagram. As the alleles assort independently hence the gametes formed will be OT,Ot,OT,Ot and OT,Ot,oT,ot. These will be the outcomes of the possible gametes formed. When these gametes are cross bred, the results are shown in the diagram attached.
Answer No 2:
The outcomes of each possible genotype are:
OOTT = 2/16
OOTt = 4/16
OOtt = 2/16
Oott = 2/16
OoTT = 2/16
OoTt = 4/16
Answer No 3:
The likelihood of each possible offspring phenotype is:
Orange petals with tall stem and orange petals with small stems present in ratio 12:4 i.e. 3:1.
Answer:D
Explanation:
Both parent are Heterozygous for the sickle cell allele.
Both parent have sickle cell trait in which the both posses one abnormal allele of the hemoglobin beta gene (AS heterozygous genotype)
When two AS parents mate, probability of giving birth to a sickle cell anemia child is 1/4
AS + AS= AA, AS, AS, SS
Answer:
1 is A 2 is D 3 is B 4 is C
Explanation:
have a nice day!!
The answer is; C
Homologous chromosomes have the same genes on the same loci. However, they may have different forms of the same gene called alleles. These sister chromosomes, of a homologous pair, separate during anaphase I of meiosis. The two daughter cells formed will, therefore, have half the genetic material as the parent cell. This is because they will only have one set of the genes (as in diploid organisms) and are called gametes.
Answer: Examples of beneficial mutations are HIV resistance, lactose tolerance, and trichromatic vision.
