<h3>
Answer: -10</h3>
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Work Shown:
First we need to evaluate f(3)
f(x) = -x^2 + 2x
f(x) = -(x)^2 + 2(x)
f(3) = -(3)^2 + 2(3) ... replace every x with 3; apply PEMDAS to simplify
f(3) = -9 + 6
f(3) = -3
Then we subtract 7 from both sides
f(3) - 7 = -3 - 7
f(3) - 7 = -10
Answer:
x=-5
Step-by-step explanation:
6x+3+10=0
6x+30=0
6x=-30
x=-30/6
x=-5
Answer:
The minimum volume of hot air needed to lift a hot air balloon carrying 800kg
Is 653.1m³
Step-by-step explanation:
This problem bothers on the density of materials in this problem air
Given data
Volume of air V=?
Mass of air m= 800kg
From tables the density of air is
ρ =1.225 kg/m3
Now to solve for the volume we have
ρ=m/v
v=m/ρ
v=800/1.225
Volume v = 653.1m³
Through the slope equation, we know that the slope, or m, is 2.
This gets us to y = 2x + b.
Next we plug in a point and get 4 = 2(3) + b, or b + 6 = 4, or b = -2.
This gives us our answer: y = 2x - 2.
Hope this helps!
