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erica [24]
3 years ago
14

Which shows a difference of squares?

Mathematics
1 answer:
laila [671]3 years ago
8 0

Answer:

2nd answer

Step-by-step explanation:

educated guess

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Solve and check equation 20 = 2r - 3r + 10
Andreas93 [3]

2r-3r+10=20

Move all terms to the left:

2r-3r+10-(20)=0

add all the numbers together, and all the variables

-1r-10=0

move all terms containing r to the left, all other terms to the right

-r=10

r=10/-1

r=-10

7 0
3 years ago
Luke and isabella make scale drawings.The scale from isabella's drawing is 6 m to 3 cm. The height of the fountain in isabella's
den301095 [7]

Answer:

The answer is "2.5 \ cm"

Step-by-step explanation:

While Luke is 5m to 2cm in size, it implies that every 2cm to Luke's drawing is 5m in real life. That real pond width must therefore be 5 m, given the fountain's width is 2 cm. As shown in the illustration, the step size for IsabelLa from the illustration to real life is \frac{6}{3} =2, which makes it simple to multiply any measure in the cm of her illustration by 2 to accomplish the exact size in m. So, in another direction around, they just have to divide the value by 2, instead of the divide from reality for drawing. So if the actual worth is 5m, it ought to be \frac{5}{2} = 2.5 \ cm in its width.

7 0
3 years ago
Can someone help me with this?
creativ13 [48]

The missing values are 28° and 62°

<h3>What are perpendicular lines?</h3>

Perpendicular lines are said to be two lines that intersect or meet each other at right angles, that is 90 degrees.

From the information given, we have that;

Line AC ⊥ Line BE

Where:

  • m ∠ ADE = (x + 5)°
  • m ∠ DBE = (3x - 7)°

Hence,

x + 5 + 3x - 7 = 90

collect like terms

4x = 90 + 2

4x = 92

Make 'x' the subject

x = 92/ 4

x = 23

For the missing values

m ∠ ADE = (x + 5)° = ( 23 + 5) = 28°

m ∠ DBE = (3x - 7)° = (3(23) - 7) = 62°

Thus, the missing values are 28° and 62°

Learn more about perpendicular lines here:

brainly.com/question/17683061

#SPJ1

8 0
1 year ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
Determine the center and radius of the following circle equation: x² + y2 - 6x + 16y + 48 = 0​
motikmotik

Answer:

center (3,-8)

radius=5

4 0
3 years ago
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