Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = 
= 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
Answer:
20
Step-by-step explanation:
y=kx
X=2 & y= 10
10=2k
k=5
when y=100
100=5x
X=20
Answer:
0.6988
Step-by-step explanation:
Given that the number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution.
Let X be the number of customers arriving between 10 and 11 am.
X is Poisson with mean= 1.2
Required probability
= the probability that in the hour between 10 and 11 PM at least one customer arrives
= P(X≥1)
=1-P(X=0)
=1-0.3012
= 0.6988
Answer:
Step-by-step explanation:
Part A.
Expression 
= 10
Because 100 = 
and ![[(10)^2]^{\frac{1}{2}}=10^1=10](https://tex.z-dn.net/?f=%5B%2810%29%5E2%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D10%5E1%3D10)
[Since, 
]
Part B.
When simplified, the answer is RATIONAL.
[Since, 10 can be written as 
]
