Question

The sum of 3 consecutive integers is 78. What is the integer closest to zero?

Answer 1

Therefore the first integer is 25
So our sequence is 25, 26 and 27 respectively
The integer closest to zero will thus be 25.

Answer 2

Answer:

25

Step-by-step explanation:

Let n be the first integer.

Then the second integer will be (n + 1).

And the third will be (n + 2).

The sum is 78. Therefore:

$n+(n+1)+(n+2)+78$

Solve for n. Combine like terms:

$3n+3=78$

So:

$3n=75$

Therefore:

$n=25$

Therefore, the first integer is 25.

So our sequene is 25, 26, and 27.

The integer closest to zero will thus be 25.