All categories

3 years ago

Use the following table below, which represents the average rainfall in Orlando to answer this questions:

Mathematics

1 answer:

MariettaO [177]3 years ago

3 0

Answer:

me no understand plz ask a teacher

You might be interested in

Which describes the location of 2 /3 on the number line? A) between 1/3 and 2 5 B) between 2 /5 and 1 /2 C) between 1 /2 and 3 /

Bas_tet [7]

Answer:

2/3 lies between 1 and 2

Option C

5 0

3 years ago

Read 2 more answers

If angle ABD is 90 degrees. Select all of the angles that measure 42 degrees.

m_a_m_a [10]

Answer:

Measure of angle 2 and angle 4 is 42°.

Step-by-step explanation:

From the figure attached,

m∠ABC = 42°

m(∠ABD) = 90°

m(∠ABD) = m(∠ABC) + m(∠DBC)

90° = 43° + m(∠DBC)

m(∠DBC) = 90 - 43 = 47°

Since ∠ABC ≅ ∠4 [Vertical angles]

m∠ABC = m∠4 = 42°

Since, m∠3 + m∠4 = 90° [Complimentary angles]

m∠3 + 42° = 90°

m∠3 = 90° - 42°

= 48°

Since, ∠5 ≅ ∠3 [Vertical angles]

m∠5 = m∠3 = 48°

m∠3 + m∠2 = 90° [given that m∠2 + m∠3 = 90°]

m∠2 + 48° = 90°

m∠2 = 90 - 48 = 42°

m∠3+ m∠4 = 90° [Since, ∠3 and ∠4 are the complimentary angles]

48° + m∠4 = 90°

m∠4 = 90 - 48 = 42°

Therefore, ∠2 and ∠4 measure 42°.

5 0

4 years ago

Must a function that is decreasing over a given interval always be negative over that same interval ? Explain

Leno4ka [110]

Check the picture below.

5 0

3 years ago

Read 2 more answers

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

6 0

3 years ago

Read 2 more answers

32x - 4 = 4x2 + 60 For the equation shown, choose the description of the solutions.

Furkat [3]

All to one side:

4x^2-32x+64 = 0,

divide by 4:

x^2 -8x + 16 = 0

apply formula or see that it is (x-4)^2!, so only x =4 is a root and it is double.

3 0

3 years ago

Read 2 more answers